What is the equation of the line with slope -2/3 and passes through the point (3, 2)?

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Answer 1 · 2016-06-09T23:45:15

The equation of the line in slope-intercept form becomes

#y = -2/3 x + 4#

The slope intercept form of a line is #y=mx+b#

For this problem we are given the slope as #-2/3# and a point on the line of #(3,2)#

#m=-2/3#
#x=3#
#y=2#

We plug in the values and then solve for the #b# term which is the
y-intercept.

#2 =-2/3(3) +b#

#2 =-2 +b#

Now isolate the #b# term.

#2 +2 =cancel(-2) cancel(+2)+b#

#b= 4#

The equation of the line in slope-intercept form becomes

#y = -2/3 x + 4#