# What is the equation of the line with slope  m= -1/13  that passes through  (-29,17) ?

Sep 15, 2016

$y = - \frac{1}{13} \left(x - 192\right)$

#### Explanation:

We have: $m = - \frac{1}{13}$ and $\left(- 29 , 17\right)$

We can use this information to write an equation in the "point-slope form": $y - {y}_{1} = m \left(x - {x}_{1}\right)$

$\implies y - \left(17\right) = \left(- \frac{1}{13}\right) \left(x - \left(- 29\right)\right)$

$\implies y - 17 = - \frac{1}{13} \left(x + 29\right)$

Let's rearrange it to "slope-intercept form":

$\implies y - 17 = - \frac{1}{13} x - \frac{29}{13}$

$\implies y = - \frac{1}{13} x - \frac{29}{13} + 17$

$\implies y = - \frac{1}{13} x + \frac{192}{13}$

$\implies y = - \frac{1}{13} \left(x - 192\right)$