What is the equation of the line with slope # m= -5/6 # that passes through # (-1/12,5/3) #?

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Answer 1 · 2018-04-26T02:57:00

#y-5/3=-5/6(x+1/12)#

We can use the point-slope form for a linear equation:

#y-y_1=m(x-x_1)#,

where:

#m# is the slope, #-5/6#, and #(x_1,y_1)# is the point #(-1/12,5/3)#.

Plug in the known values.

#y-5/3=-5/6(x-(-1/12))#

Simplify.

#y-5/3=-5/6(x+1/12)#

If you wish to convert this to slope-intercept form, solve for #y#.