We can use the slope-point formula to identify the line with the given slope and point.

The point-slope formula states: #color(red)((y - y_1) = m(x - x_1))#

Where #color(red)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the information we were provided into this formula gives:

#y - -3/10 = 7/25(x - 41/5)#

#y + 3/10 = 7/25(x - 41/5)#

If we want to convert to slope-intercept form (#y = mx + b#) we can solve for #y# as follows:

#y + 3/10 = 7/25x - (7/25 xx 41/5)#

#y + 3/10 = 7/25x - 287/125#

#y + 3/10 - color(red)(3/10) = 7/25x - 287/125 - color(red)(3/10)#

#y + 0 = 7/25x - 287/125 - color(red)(3/10)#

#y = 7/25x - 287/125 - color(red)(3/10)#

#y = 7/25x - (287/125 xx 2/2) - (color(red)(3/10) xx 25/25)#

#y = 7/25x - 574/250 - 75/250#

#y = 7/25x - 649/250#