What is the equation of the line with slope # m= -8/3 # that passes through # (-17/15,-15/24) #?

1 Answer
Jun 9, 2017

See a solution process below:

Explanation:

We can use the point-slope formula to write an equation for this line. The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #(color(red)(x_1, y_1))# is a point the line passes through.

Substituting the slope and values from the point in the problem gives:

#(y - color(red)(-15/24)) = color(blue)(-8/3)(x - color(red)(-17/15))#

#(y + color(red)(15/24)) = color(blue)(-8/3)(x + color(red)(17/15))#

We can also solve this equation for #y# to transform it to slope-intercept form. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

#y + color(red)(15/24) = (color(blue)(-8/3) xx x) + (color(blue)(-8/3) xx color(red)(17/15))#

#y + color(red)(15/24) = -8/3x - 136/45#

#y + color(red)(15/24) - 15/247 = -8/3x - 136/45 - 15/24#

#y + 0 = -8/3x - (24/24 xx 136/45) - (45/45 xx 15/24)#

#y = -8/3x - (3264/1080) - (675/1080)#

#y = -8/3x - 3939/1080#

#y = -8/3x - (3 xx 1313)/(3 xx 360)#

#y = -8/3x - (color(red)(cancel(color(black)(3))) xx 1313)/(color(red)(cancel(color(black)(3))) xx 360)#

#y = -8/3x - 1313/360#