What is the full ground state electron configuration of #O^+#?

1 Answer
Nov 20, 2016

Answer:

#O^+=1s^(2)2s^(2)2p^3#

Explanation:

Typically, an atom of #O# has 8 electrons, so based on the electron configuration system that would be #1s^(2)2s^(2)2p^(4)#, or #2+2+4=8e^-#.

However, #O^+# means you've lost an electron, hence the positive charge. Thus, you subtract an electron:
#8\color(teal)(-1)=\color(red)(7)e^-#
#1s^(2)2s^(2)2p^(4\color(teal)(-1))\rArr1s^(2)2s^(2)2p^(\color(red)(3))#

Electron configuration rule:
http://imgarcade.com/1/electron-configuration-chart/