What is the full ground state electron configuration of O^+?

1 Answer
Nov 20, 2016

O^+=1s^(2)2s^(2)2p^3

Explanation:

Typically, an atom of O has 8 electrons, so based on the electron configuration system that would be 1s^(2)2s^(2)2p^(4), or 2+2+4=8e^-.

However, O^+ means you've lost an electron, hence the positive charge. Thus, you subtract an electron:
8\color(teal)(-1)=\color(red)(7)e^-
1s^(2)2s^(2)2p^(4\color(teal)(-1))\rArr1s^(2)2s^(2)2p^(\color(red)(3))

Electron configuration rule:
http://imgarcade.com/1/electron-configuration-chart/http://imgarcade.com/1/electron-configuration-chart/