Question

What is the full ground state electron configuration of `O^+`?

Answer 1

`O^+=1s^(2)2s^(2)2p^3`

Explanation:

Typically, an atom of `O` has 8 electrons, so based on the electron configuration system that would be `1s^(2)2s^(2)2p^(4)`, or `2+2+4=8e^-`.

However, `O^+` means you've lost an electron, hence the positive charge. Thus, you subtract an electron:
`8\color(teal)(-1)=\color(red)(7)e^-`
`1s^(2)2s^(2)2p^(4\color(teal)(-1))\rArr1s^(2)2s^(2)2p^(\color(red)(3))`

Electron configuration rule: