# What is the ground-state electron configuration of Pb?

The ground-state electron configuration of $\text{Pb}$ is:
["Xe"]"4f"^(14)"5d"^(10)"6s"^2"6p"^2
Lead $\left(\text{Pb}\right)$ has atomic number $82$. This means that all atoms of lead have $82$ protons in their nuclei. In a neutral lead atom, there will also be $82$ electrons in the electron cloud. The ground-state electron configuration of $\text{Pb}$ is:
["Xe"]"4f"^(14)"5d"^(10)"6s"^2"6p"^2