What is the ground state electron configuration of Se?

Oct 21, 2015

$\left[A r\right] 3 {d}^{10} 4 {s}^{2} 4 {p}^{4}$

Explanation:

Selenium has 34 electrons so in electron shell notation this is:

$2.8 .18 .6$

The noble gas shorthand using orbital notation is therefore:

$\left[A r\right] 3 {d}^{10} 4 {s}^{2} 4 {p}^{4}$