What is the %-ionization in a 0.20M solution of a weak acid, HA?

1 Answer
Aug 12, 2017

Answer:

Unknown.......

Explanation:

You have the weak acid undergoing protonolysis in aqueous solution:

#HA(aq) + H_2O(l) rarrH_3O^(+) + A^(-)#

Now we calculate the extent of this equilibrium by use of the equation, #K_a=([H_3O^+][A^-])/([HA])#. But we ain't got a value of #K_a#; typical values of #K_a# for the weak acid #H_3C-CO_2H#, #K_a=1.73xx10^-5#; for #HF#, #K_a=6.76xx10^-4#; and for water, #K_a=10^-14#.

Over to you......