What is the magnetic moment of ? 1. CuCl2 and TiCl3 2.MnCl2 and CuSO4

1 Answer
Jun 3, 2018

Answer:

We can address the #"spin only moments"#....#mu_"spin only"=sqrt(n(n+2))#...where #n="number of unpaired electrons..."#

Explanation:

For #"cupric chloride"#, and #"titanium(III) chloride"# we gots #d^9# and #d^1# systems respectively....and an electron HOLE, i.e. #Cu(II^+)#, is equivalent to a single electron. The spin-only moment is #1.73*mu_"B"#..(you will have to look up the #"Bohr Magneton unit")#.

As for #"cupric sulfate"# we got another #d^9# system... And as for #MnCl_2# we got a #d^5# system....which are GENERALLY high-spin....#mu_"spin only"=sqrt(35)=5.9*mu_"B"#...this approximation is much less likely to be valid...