# What is the magnetic moment of ? 1. CuCl2 and TiCl3 2.MnCl2 and CuSO4

We can address the $\text{spin only moments}$....${\mu}_{\text{spin only}} = \sqrt{n \left(n + 2\right)}$...where $n = \text{number of unpaired electrons...}$
For $\text{cupric chloride}$, and $\text{titanium(III) chloride}$ we gots ${d}^{9}$ and ${d}^{1}$ systems respectively....and an electron HOLE, i.e. $C u \left(I {I}^{+}\right)$, is equivalent to a single electron. The spin-only moment is $1.73 \cdot {\mu}_{\text{B}}$..(you will have to look up the "Bohr Magneton unit").
As for $\text{cupric sulfate}$ we got another ${d}^{9}$ system... And as for $M n C {l}_{2}$ we got a ${d}^{5}$ system....which are GENERALLY high-spin....${\mu}_{\text{spin only"=sqrt(35)=5.9*mu_"B}}$...this approximation is much less likely to be valid...