# What is the mass of 25.0 cm^3 of gold?

Gold has a density, $\rho$ $=$ $19.32$ $g \cdot c {m}^{-} 3$. This very high density allows ALLUVIAL gold to be panned....i.e. separated by mass...
For mass, we simply take the product, $\text{volume "xx" density}$, i.e. $25.0 \cdot \cancel{c {m}^{3}} \times 19.32 \cdot g \cdot \cancel{c {m}^{-} 3}$ $=$ ?? g