What is the orthocenter of a triangle with corners at (4 ,9 ), (7 ,4 ), and (8 ,1 )#?

1 Answer
Jul 30, 2018

Orthocenter: (43,22)

Explanation:

The orthocenter is the intersecting point for all the altitudes of the triangle. When given the three coordinates of a triangle, we can find equations for two of the altitudes, and then find where they intersect to get the orthocenter.

Let's call color(red)((4,9), color(blue)((7,4), and color(green)((8,1) coordinates color(red)(A, color(blue)(B, and color(green)(C respectively. We'll find equations for lines color(crimson)(AB and color(cornflowerblue)(BC. To find these equations, we'll need a point and a slope. (We'll use the point-slope formula).

Note: The slope of the altitude is perpendicular to the slope of the lines. The altitude will touch a line and the point that lies outside of the line.

First, let's tackle color(crimson)(AB:

Slope: -1/({4-9}/{7-4})=3/5

Point: (8,1)

Equation: y-1=3/5(x-8)->color(crimson)(y=3/5(x-8)+1

Then, let's find color(cornflowerblue)(BC:

Slope: -1/({1-4}/{8-7})=1/3

Point: (4,9)

Equation: y-9=1/3(x-4)->color(cornflowerblue)(y=1/3(x-4)+9

Now, we just set the equations equal to each other, and the solution would be the orthocenter.

color(crimson)(3/5(x-8)+1)=color(cornflowerblue)(1/3(x-4)+9

(3x)/5-24/5+1=(x)/3-4/3+9

-24/5+1+4/3-9=(x)/3-(3x)/5

-72/15+15/15+20/15-135/15=(5x)/15-(9x)/15

-172/15=(-4x)/15

color(darkmagenta)(x=-172/15*-15/4=43

Plug the x-value back into one of the original equations to get the y-coordinate.

y=3/5(43-8)+1
y=3/5(35)+1
color(coral)(y=21+1=22

Orthocenter: (color(darkmagenta)(43),color(coral)(22))