What is the orthocenter of a triangle with corners at (9 ,7 ), (2 ,4 ), and (8 ,6 )#?

1 Answer
Jul 30, 2018

The orthocenter of triangle is (14,-8)

Explanation:

Let triangleABC " be the triangle with corners at"

A(9,7), B(2,4) and C(8,6)

Let bar(AL) , bar(BM) and bar(CN) be the altitudes of sides bar(BC) ,bar(AC) and bar(AB) respectively.

Let (x,y) be the intersection of three altitudes .

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Slope of bar(AB) =(7-4)/(9-2)=3/7

bar(AB)_|_bar(CN)=>slope of bar(CN)=-7/3 ,

bar(CN) passes through C(8,6)

:.The equn. of bar(CN) is :y-6=-7/3(x-8)

3y-18=-7x+56

i.e. color(red)(7x+3y=74.....to (1)

Slope of bar(BC) =(6-4)/(8-2)=2/6=1/3

bar(AL)_|_bar(BC)=>slope of bar(AL)=-3 , bar(AL) passes through A(9,7)

:.The equn. of bar(AL) is :y-7=-3(x-9)=>y-7=-3x+27

=>3x+y=34

i.e. color(red)(y=34-3x.....to (2)

Subst. color(red)(y=34-3x into (1) ,we get

7x+3(34-3x)=74=>7x+102-9x=74=>-2x=-28
=>color(blue)( x=14

From equn.(2) we get

y=34-3(14)=34-42=>color(blue)(y=-8

Hence, the orthocenter of triangle is (14,-8)