Question

What is the period and amplitude for `y=2tan(3x-pi2)`?

Answer 1

Amplitude= `oo`
Period= `(pi^2+pi)/3`

Explanation:

The amplitude is infinity. Because the `tan` function is increasing over its whole domain of definition.
graph{tanx [-10, 10, -5, 5]}

The period of any `tan` is the value of `x` when the "inside" of the `tancolor(red)()` function equals `pi`.

I'll assume that,
`y=2tan(3x-pi^2)`

For a period `3x-pi^2=pi`

`=>x=(pi^2+pi)/3`