# What is the period of f(t)=sin( ( 4t ) /3 ) ?

Dec 24, 2015

Period is $\frac{3 \pi}{2}$

#### Explanation:

Period of function of form $\sin \left(B x\right)$ is $\frac{2 \pi}{B}$.

Our function is $f \left(t\right) = \sin \left(\frac{4 t}{3}\right)$

On comparing with $\sin \left(B x\right)$ we get $B = \frac{4}{3}$

The using the rule $\frac{2 \pi}{B}$ we get the period as

Period =$\frac{2 \pi}{\frac{4}{3}}$

Simplifying we get Period = $\frac{3 \pi}{2}$