What is the period of f(theta) = tan ( ( 12 theta)/7 )- sec ( ( 14 theta)/ 6 ) ?

1 Answer
Jan 9, 2018

42pi

Explanation:

Period of tan ((12t)/7) --> (7pi)/12
Period of sec ((14t)/6) --> ((6)(2pi))/14 = (6pi)/7
Period of f(t) is least common multiple of (7pi)/12 and (6pi)/7.

(6pi)/7........ x (7)(7) .... --> 42pi
(7pi)/12 ...... x (12)(6) .... --> 42pi