What is the pOH of a 8.4x10^-11 M OH^- solution?

1 Answer
Aug 28, 2016

pOH=10.08

Explanation:

The pOH of a solution is defined in terms of the concentration of hydroxide ions in solution as follows:

pOH=-log[OH^(-)].

In this question, [OH^(-)]=8.4xx10^(-11)M, thus the pOH can be calculated by:

pOH=-log(8.4xx10^(-11))=10.0757~=10.08

Note that if the concentration is given with 2 significant figures , the pOH value is written with two decimal places.