# What is the position of an element in the periodic table if its electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^5?

Dec 16, 2016

$n {S}^{2} n {P}^{1 - 6}$
Here $n = 3$ and the condition is maintained.
Hence we get that the period of the element of the element is $3$ and the group in the long periodic table is 17.