Question

What is the shorthand electron configuration for Au?

Answer 1

So, what is the atomic number of gold?

Explanation:

For gold, `Z=79`...and we gots 79 electrons to distribute.. Following the `"aufbau scheme"`, we build on the configuration of the last Noble gas, i.e. `Xe, Z=54`. Of course, we got a whole lanthanide series, cerium to lutetium, between xenon and goldo…

Let's try `Au:underbrace([Xe])_"54 electrons"4f^(14)5d^(10)6s^1`

Does the electornic charge balance the atomic number? If the answer is no, then my answer must be wrong....