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What is the shorthand electron configuration for Ni?

1 Answer

Apr 24, 2016

$N i, Z = 28$ $Ni, Z =28$ ; $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{8}$ $1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^8$

We go back to the last Noble gas ( $A r, Z = 18$ $Ar, Z=18$ ) to get......

Explanation:

$N i, Z = 28$ $Ni, Z =28$ . $[A r] 4 s^{2} 3 d^{8}$ $[Ar]4s^(2)3d^(8)$ .

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