# What is the shorthand electron configuration for Ni?

$N i , Z = 28$; $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{8}$
We go back to the last Noble gas ($A r , Z = 18$) to get......
$N i , Z = 28$. $\left[A r\right] 4 {s}^{2} 3 {d}^{8}$.