# What is the shorthand electron configuration of neon?

$\left[H e\right] 2 {s}^{2} 2 {p}^{6}$
Neon's electron configuration is $1 {s}^{2} 2 {s}^{2} 2 {p}^{6}$
The shorthand is always based on the previous noble gas. All noble gases except for Helium end in $n {s}^{2} n {p}^{6}$, where $n$ is the period or row.
So Neon's shorthand is $\left[H e\right] 2 {s}^{2} 2 {p}^{6}$