What is the simplest radical form of 2sqrt112?

Aug 15, 2017

$8 \sqrt{7}$

Explanation:

Write the radicand as the product of its factors.
Usually prime factors is advisable, but in this case

$112 = 16 \times 7$

which is very useful because $16$ is a square number.

$2 \sqrt{112}$

$= 2 \sqrt{\textcolor{red}{16} \times 7} \text{ } \leftarrow$ find the roots if possible

$= 2 \times \textcolor{red}{4} \sqrt{7}$

$= 8 \sqrt{7}$