What is the simplest radical form of #2sqrt112#?

1 Answer
Aug 15, 2017

Answer:

#8sqrt7#

Explanation:

Write the radicand as the product of its factors.
Usually prime factors is advisable, but in this case

#112 = 16xx7#

which is very useful because #16# is a square number.

#2sqrt112#

# = 2sqrt(color(red)(16) xx7)" "larr# find the roots if possible

#=2 xx color(red)(4)sqrt7#

#=8sqrt7#