What is the slope and y-intercept of this line 15x - 3y = -90?

Jun 2, 2018

See a solution process below:

Explanation:

This equation is in Standard Linear form. The standard form of a linear equation is: $\textcolor{red}{A} x + \textcolor{b l u e}{B} y = \textcolor{g r e e n}{C}$

Where, if at all possible, $\textcolor{red}{A}$, $\textcolor{b l u e}{B}$, and $\textcolor{g r e e n}{C}$are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

The slope of an equation in standard form is: $m = - \frac{\textcolor{red}{A}}{\textcolor{b l u e}{B}}$

The $y$-intercept of an equation in standard form is: $\frac{\textcolor{g r e e n}{C}}{\textcolor{b l u e}{B}}$

$\textcolor{red}{15} x - \textcolor{b l u e}{3} y = \textcolor{g r e e n}{- 90}$

Or

$\textcolor{red}{15} x + \left(\textcolor{b l u e}{- 3} y\right) = \textcolor{g r e e n}{- 90}$

Therefore:

• The slope of the line is: $m = \frac{- \textcolor{red}{15}}{\textcolor{b l u e}{- 3}} = 5$

• The $y$-intercept is: $\frac{\textcolor{g r e e n}{C}}{\textcolor{b l u e}{B}} = \frac{- 90}{- 3} = 30$ or $\left(0 , 30\right)$