# What is the slope and y-intercept of this line y = (-4/5)x + 1?

Aug 13, 2016

slope$= - \frac{4}{5}$
$y$-intercept is $y = 1$

#### Explanation:

$y = m x + c$ where $m$ is the slope
$y = \left(- \frac{4}{5}\right) x + 1$
Hence slope$= - \frac{4}{5}$-------------------------Ans $1$
$y$-intercept is when $x = 0$
By plugging the value $x = 0$ inthe equation $y = \left(- \frac{4}{5}\right) x + 1$
we get
$y = - \frac{4}{5} \times 0 + 1$
or
$y = 0 + 1$
or
$y = 1$-----------------------------Ans $2$

Aug 13, 2016

slope = $- \frac{4}{5}$
y-intercept = 1

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{slope-intercept form}}$ is

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{y = m x + b} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
where m represents the slope and b, the y-intercept.

The advantage to having the equation in this form, is that m and b may be extracted 'easily'.

The equation here $y = - \frac{4}{5} x + 1 \text{ is in this form}$

$\Rightarrow \text{slope" =-4/5" and y-intercept} = 1$