What is the slope intercept form of the line with a slope of #-5/4 # and y-intercept of # -2/3 #?

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Answer 1 · 2016-03-08T11:41:54

#15x+12y+8=0#

The slope intercept form of the line with a slope of #m# and and #y#-intercept of #c# is given by

#y=mx+c#

Hence, slope intercept form of the line with a slope of #-5/4# and and #y#-intercept of #-2/3# is

#y=(-5/4)x+(-2/3)# and multiplying by #12# this becomes

#12y=12xx(-5/4)x+12xx(-2/3)# or

#12y=-15x-8#

or #15x+12y+8=0#