# What is the slope of the tangent line of #sqrt(y-e^(x-y))= C #, where C is an arbitrary constant, at #(-2,1)#?

##### 1 Answer

#### Answer:

Equation of tangent is

#### Explanation:

As tangent is saught at the point

i.e.

Hence function is

or

As slope of tangent is the value of first derivative at the point, here

or

i.e.

Hence, slope of tangent is

and equation of tangent is

graph{(sqrt(y-e^(x-y))-sqrt(1-1/e^3))(x-(e^3+1)y+3+e^3)=0 [-11.29, 8.71, -4.52, 5.48]}