# What is the solution of the system 3x - y = 3 and 2x + y = 2?

Mar 27, 2015

Given
$3 x - y = 3$ and
$2 x + y = 2$

By adding the two equations together, we get
$5 x + 0 = 5$
So
$x = 1$

Substituting $x = 1$ back into the first equation:
$3 \left(1\right) - y = 3$
which implies
$y = 0$

The solution to the given equations is
$\left(x , y\right) = \left(1 , 0\right)$