What is the square root of a^2\b^5?

2 Answers
May 30, 2018

Answer:

#=(asqrtb)/(b^3)#

Explanation:

I assume you meant:

#=sqrt(a^2/b^5)#

#=sqrt(a^2)/sqrt(b^5)#

#=a/(b^2sqrt(b))#

now you need to rationalize the denominator by multiplying the expression by:

#sqrtb/sqrtb#

#=a/(b^2sqrt(b))*sqrtb/sqrtb#

#=(asqrtb)/(b^2*b)#

#=(asqrtb)/(b^3)#

May 30, 2018

Answer:

#(a sqrt b)/b^3#

Explanation:

#sqrt(a^2/b^5)#

#:.=sqrt (a^2)/sqrt (b^5)#

#:.=(sqrt (a*a))/sqrt (b*b*b*b*b)#

#:.sqrt (a)*sqrt (a)=a#

#:.sqrt (b)*sqrt (b)=b#

#:.=a/(b^2 sqrt b) xx(b^2sqrtb)/(b^2sqrtb)#

#:.=(ab^2 sqrt b)/b^5#

#:.=(a sqrt b)/b^(5-2)#

#:.=(a sqrt b)/b^3#