# What is the standard form of a polynomial (2y-8)(y-4)?

Mar 21, 2017

See the entire solution process below:

#### Explanation:

We need to multiply these two terms to put the expression in the standard form of a polynomial. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$\left(\textcolor{red}{2 y} - \textcolor{red}{8}\right) \left(\textcolor{b l u e}{y} - \textcolor{b l u e}{4}\right)$ becomes:

$\left(\textcolor{red}{2 y} \times \textcolor{b l u e}{y}\right) - \left(\textcolor{red}{2 y} \times \textcolor{b l u e}{4}\right) - \left(\textcolor{red}{8} \times \textcolor{b l u e}{y}\right) + \left(\textcolor{red}{8} \times \textcolor{b l u e}{4}\right)$

$2 {y}^{2} - 8 y - 8 y + 32$

We can now combine like terms:

$2 {y}^{2} + \left(- 8 - 8\right) y + 32$

$2 {y}^{2} - 16 y + 32$