Question

What is the the vertex of `y = (x-1)^2+x-12`?

Answer 1

Vertex is `(1/2,-11 1/4)`

Explanation:

Vertex form of equation is `y=a(x-h)^2+k`, where `(h,k)` is the vertex.

Now `y=(x-1)^2+x-12`

= `x^2-2x+1+x-12`

= `x^2-x-11`

= `x^2-2xx1/2xx x+(1/2)^2-1/4-11`

= `(x-1/2)^2-45/4`

Hence `y=(x-1)^2+x-12hArry=(x-1/2)^2-45/4`

and vertex is `(1/2,-11 1/4)`

graph{(x-1)^2+x-12 [-19.83, 20.17, -14.16, 5.84]}