# What is the the vertex of #y=x^2+15x-30#?

##### 1 Answer

Jun 3, 2016

I found:

#### Explanation:

There are two ways to find the coordinates of the vertex:

1) knowing that the

in your case:

so:

by substituting this value into your original equation you get the corresponding

2) usig the derivative (but I am not sure you know this procedure):

Derive your function:

set it equal to zero (to find the point of zero slope...the vertex):

i.e.

and solve to get:

Graphically:

graph{x^2+15x-30 [-240.5, 240.3, -120.3, 120.3]}