What is the third term in the expansion of# (cos x+3)^5#?

1 Answer
Jul 14, 2016

We use the formula #t_(k + 1)=color(white)(two)_nC_k(x)^(n - k) xx y^k#, where #color(white)(two)_nC_k# denotes the combination formula in the context of #(x + y)^n#.

Since we're looking for the third term, #k + 1 = 3 ->k = 2#.

#t_3 = color(white)(two)_5C_2 xx (cosx)^(5 - 2) xx 3^2#

#t_3 = (5!)/((5 - 2)! xx 2!) xx (cosx)^3 xx 9#

#t_3 = 10 xx cos^3x xx 9#

#t_3 = 90cos^3x#

Hopefully this helps!