Question

What is the trigonometric form of `3 e^( ( pi)/12 i )`?

Answer 1

I found: `3(cos(pi/12)+isin(pi/12))`

Explanation:

You can change it as:
`rhoe^(itheta)=rho(cos(theta)+isin(theta))`
In your case:
`3e^(pi/12i)=3(cos(pi/12)+isin(pi/12))`