# What is the trigonometric form of  3 e^( ( pi)/12 i ) ?

I found: $3 \left(\cos \left(\frac{\pi}{12}\right) + i \sin \left(\frac{\pi}{12}\right)\right)$
$\rho {e}^{i \theta} = \rho \left(\cos \left(\theta\right) + i \sin \left(\theta\right)\right)$
$3 {e}^{\frac{\pi}{12} i} = 3 \left(\cos \left(\frac{\pi}{12}\right) + i \sin \left(\frac{\pi}{12}\right)\right)$