# What is the trigonometric form of  8 e^( ( 5 pi)/12 i ) ?

Mar 22, 2016

$8 \left[\cos \left(\frac{5 \pi}{12}\right) + i \sin \left(\frac{5 \pi}{12}\right)\right]$

#### Explanation:

Using$\textcolor{b l u e}{\text{ Euler's identity}}$ which states :

$r {e}^{\theta i} = r \left(\cos \theta + i \sin \theta\right)$

here r = 8 and $\theta = \frac{5 \pi}{12}$

$\Rightarrow 8 {e}^{\frac{5 \pi}{12} i} = 8 \left[\cos \left(\frac{5 \pi}{12}\right) + i \sin \left(\frac{5 \pi}{12}\right)\right]$