# What is the vertex form of 1y=7x^2 + 5x - 11?

Dec 17, 2015

Find vertex of $y = 7 {x}^{2} + 5 x - 11$

Vertex $\left(- \frac{5}{14} , \frac{1981}{146}\right)$

#### Explanation:

x-coordinate of vertex: $x = \frac{- b}{2} a = - \frac{5}{14}$
y-coordinate of vertex:
y = y(-5/14) = 7(25/196) + 5(-5/14) - 11 = = 175/196 - 25/14 - 11 = 1981/196#
Vertex form: $y = 7 {\left(x + \frac{5}{14}\right)}^{2} + \frac{1981}{196}$