Question

What is the vertex form of #1y=7x^2 + 5x - 11?

Answer 1

Find vertex of `y = 7x^2 + 5x - 11`

Vertex `(-5/14, 1981/146)`

Explanation:

x-coordinate of vertex: `x = (-b)/2a = -5/14`
y-coordinate of vertex:
#y = y(-5/14) = 7(25/196) + 5(-5/14) - 11 = = 175/196 - 25/14 - 11 = 1981/196#
Vertex form: `y = 7(x + 5/14)^2 + 1981/196`