# What is the vertex form of 3y = 5x^2+5x-12?

$y = \frac{5}{3} {\left(x + \frac{1}{2}\right)}^{2} - \frac{53}{12}$
$y = \frac{5}{3} \cdot {x}^{2} + \frac{5}{3} \cdot x - 4 = \frac{5}{3} \left({x}^{2} + x + \frac{1}{4}\right) - \frac{5}{12} - 4 = \frac{5}{3} {\left(x + \frac{1}{2}\right)}^{2} - \frac{53}{12}$ Vertex is at $\left(- \frac{1}{2} , - \frac{53}{12}\right)$ graph{5/3x^2+5/3x-4 [-10, 10, -5, 5]}[Ans]