Question

What is the vertex form of # f(x) = 6x^2+4x-3 #?

Answer 1

The answer is `=6(x+1/3)^2-11/9`

Explanation:

We look for the vertex form by completing the squares

`f(x)=6x^2+4x-3`

`=6(x^2+4/6x)-3`

`=6(x^2+2/3x+1/9)-3-6/9`

`=6(x+1/3)^2-11/9`

This is the vertex form