# What is the vertex form of the parabola whose standard form equation is y=5x^2-30x+49?

Nov 11, 2016

The vertex is $= \left(3 , 4\right)$

#### Explanation:

Let's rewrite the equation and complete the squares

$y = 5 {x}^{2} - 30 x + 49 = 5 \left({x}^{2} - 6 x\right) + 49$
$= 5 \left({x}^{2} - 6 x + 9\right) + 49 - 45$
$= 5 {\left(x - 3\right)}^{2} + 4$

graph{5x^2-30x+49 [-12.18, 13.14, -0.18, 12.47]}