What is the vertex form of #x = (5y +3 )^2 + 2x+1#?
1 Answer
The vertex form for a parabola of this type is:
where
Explanation:
Given:
Here is a graph of the original equation:
graph{x = (5y +3 )^2 + 2x+1 [-10, 10, -5, 5]}
Factor out a 5 from within the square:
Use the rules of squaring:
The sign within the square must be negative:
Subtract
Multiply both sides by -1:
The is the same form as equation [1] where
Here is a graph of the vertex form:
graph{x = -25(y - (-3/5))^2-1 [-10, 10, -5, 5]}
Please observe that the graphs are identical.