# What is the vertex form of y = 12x^2 -12x + 16?

Vertex form of equation is $y = 12 {\left(x - \frac{1}{2}\right)}^{2} + 13$
$y = 12 {x}^{2} - 12 x + 16 = 12 \left({x}^{2} - x\right) + 16 = 12 \left({x}^{2} - x + {\left(\frac{1}{2}\right)}^{2}\right) - 3 + 16 = 12 {\left(x - \frac{1}{2}\right)}^{2} + 13 \therefore$Vertex is at $\left(\frac{1}{2} , 13\right)$& vertex form of equation is $y = 12 {\left(x - \frac{1}{2}\right)}^{2} + 13 \therefore$ graph{12x^2-12x+16 [-80, 80, -40, 40]}[Ans]