Question

What is the vertex form of `y = 12x^2 -4x + 6`?

Answer 1

`y=12(x-1/6)^2+17/3`

Explanation:

`y=12x^2-4x+6`

Factor out the `a` value to make the numbers smaller and easier to use:
`y=12[x^2-1/3x+1/2]`

Rewrite what's inside the brackets by completing the square
`y=12[(x-1/6)^2+(1/2-1/36)]`

`y=12[(x-1/6)^2+17/36]`

Finally distribute the 12 back
`y=12(x-1/6)^2+17/3`