# What is the vertex form of  y = −25x^2 − 4x+3 ?

Jan 27, 2016

$y = - 25 {\left(x + \frac{2}{25}\right)}^{2} - \frac{129}{625}$

#### Explanation:

The equation needs to be rewritten into the form $y = a {\left(x - h\right)}^{2} + k$, where $\left(h , k\right)$ is the vertex.

$y = - 25 \left({x}^{2} + \frac{4}{25} x - \frac{3}{25}\right)$

$y = - 25 {\left(x + \frac{2}{25}\right)}^{2} - \frac{4}{625} - \frac{3}{25}$

$y = - 25 {\left(x + \frac{2}{25}\right)}^{2} - \frac{129}{625}$

The vertex is $\left(- \frac{2}{25} , - \frac{129}{625}\right)$