Question

What is the vertex form of `y=2x^2 + 13x + 6`?

Answer 1

`1/2(y-(-121/8))=(x--13/4)^2`

Explanation:

From the given
`y=2x^2+13x+6`

perform completing the square method

factor out 2 first

`y=2(x^2+(13x)/2)+6`

`y=2(x^2+(13x)/2+169/16-169/16)+6`

`y=2((x+13/4)^2-169/16)+6`

`y=2(x+13/4)^2-169/8+6`

`y=2(x+13/4)^2-169/8+48/8`

`y=2(x+13/4)^2-121/8`

`1/2(y-(-121/8))=(x--13/4)^2`

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