What is the vertex form of #y= 2x^2-16x+32 #?
To find the vertex form, you need to complete the square. So set the equation equal to zero, then separate the coefficient of x, which is 2:
Move the ones (16) to the other side, then add "c" to complete the square.
To find c, you need to divide the middle number by 2, and then square that number. so because
Then you need to multiply the coefficient back into the equation: