What is the vertex form of y=3x^2+12x+4?

Feb 10, 2017

y=$3 {\left(x + 2\right)}^{2} - 8$

Vertex is (-2,-8)

Explanation:

$y = 3 \left({x}^{2} + 4 x\right) + 4$

=$3 \left({x}^{2} + 4 x + 4 - 4\right) + 4$

=$3 \left({x}^{2} + 4 x + 4\right) - 12 + 4$

=$3 {\left(x + 2\right)}^{2} - 8$

This is the required vertex form. The vertex of the parabola is(-2,-8).