Question

What is the vertex form of `y=3x^2+12x+4`?

Answer 1

y=`3(x+2)^2 -8`

Vertex is (-2,-8)

Explanation:

`y= 3(x^2 +4x) +4`

=`3(x^2 +4x +4-4) +4`

=`3(x^2+4x+4) -12+4`

=`3(x+2)^2 -8`

This is the required vertex form. The vertex of the parabola is(-2,-8).