What is the vertex form of #y=3x^2-18x+3#?

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Answer 1 · 2016-06-27T05:06:32

the vertex is (3, -24)

The x-coordinate of the vertex is given by:

#x=-b/(2a)#

when #y=ax^2+bx+c#

Since a=3, b=-18 and c=3, you have

#x=-(-18)/(2*3)#

#x=3#

You can obtain the y-coordinate of the vertex by substituting the value of x in the equation so that

#y=3*3^2+(-18)*3+3#

#y=27-54+3#

#y=-24#