# What is the vertex form of y=-3x^2 + 6x -2 ?

Jul 29, 2016

$y = - 3 {\left(x - 1\right)}^{2} + 1$

#### Explanation:

x-coordinate of vertex:
$x = - \frac{b}{2 a} = - \frac{6}{-} 6 = 1$
y-coordinate of vertex:
y(1) = -3 + 6 - 2 = 1
Vertex (1, 1)
Vertex form of y;
y = a(x + b/(2a))^2 + y(-b/(2a)
$y = - 3 {\left(x - 1\right)}^{2} + 1$