Question

What is the vertex form of `y= 4x^2 + 17x + 4`?

Answer 1

`y = 4(x + 17/8)^2 - 140.5`

Explanation:

First, find x-coordinate of vertex:
`x = -b/(2a) = -17/8`
Next, find y-coordinate of vertex
#y(-17/8) = 4(289/64) - 17(17/8) + 4 = 1156/64 - 289/8 + 4 = = -1156/8 + 32/8 = - 1124/8 = -140.5#
Vertex form:
`y = 4(x + 17/8)^2 - 140.5`