Question

What is the vertex form of `y=4x^2+19x - 5`?

Answer 1

Vertex form of equation is `y = 4 (x+2.375)^2-27.5625`

Explanation:

`y=4x^2+19x-5 or y = 4 (x^2+19/4x) -5 or y = 4 (x^2+19/4x +19^2/8^2)-4*19^2/8^2 -5` or

`y = 4 (x+19/8)^2-361/16 -5 or y = 4 (x+19/8)^2-441/16` or

`y = 4 (x+2.375)^2-27.5625` Comparing with standard vertex form of equation `y=a(x-h)^2 + k ;(h.k)` being vertex.

We get vertex at `(-2.375, -27.5625)`

Vertex form of equation is `y = 4 (x+2.375)^2-27.5625` [Ans]