# What is the vertex form of y=4x^2-49x - 5 ?

##### 1 Answer
Dec 5, 2015

vertex $\left(\frac{- 49}{8} , 445 \frac{3}{16}\right)$

#### Explanation:

Given -
$y = 4 {x}^{2} - 49 x - 5$

If the quadratic equation is in the form
$a {x}^{2} + b x + c$ then its vertex is given by $\frac{- b}{2 a}$

x $= \frac{- 49}{2 \times 4} = \frac{- 49}{8}$

At $x = \frac{- 49}{8}$

$y = 4 \left(\frac{- 49}{8}\right) - 49 \left(\frac{- 49}{8}\right) - 5 = 445 \frac{3}{16}$

vertex $\left(\frac{- 49}{8} , 445 \frac{3}{16}\right)$