Question

What is the vertex form of `y=4x^2-49x - 5`?

Answer 1

vertex `((-49)/8, 445 3/16)`

Explanation:

Given -
`y= 4x^2 -49x-5`

If the quadratic equation is in the form
`ax^2+bx+c` then its vertex is given by `(-b)/(2a)`

x `= (-49)/(2 xx 4)=(-49)/8`

At `x=(-49)/8`

`y=4((-49)/8)-49((-49)/8)-5=445 3/16`

vertex `((-49)/8, 445 3/16)`